Answer Key
All values of pH, pOH, [H+], [OH-] can be found by using the formulas which are restated below and then entering these into a scientific calculator.
pH = -log [H+]
[H+] = 2nd Fn log [ -pH]
pOH = -log [OH-]
[OH-] = 2nd Fn log [ -pOH]
pH + pOH = 14
[H+][OH-] = 1x10-14 (1E-14)
pH = -log [H+]
[H+] = 2nd Fn log [ -pH]
pOH = -log [OH-]
[OH-] = 2nd Fn log [ -pOH]
pH + pOH = 14
[H+][OH-] = 1x10-14 (1E-14)
1.
pH = 6.65 pOH = 7.35 [H+] = 2.24 e-7 [OH-] = 4.46 e-8 2. pH = 2.65 pOH = 11.35 [H+] = 2.24 e-3 [OH-] = 4.47 e-12 3. pH = 2.86 pOH = 11.14 [H+] = 1.4e-3 [OH-] = 7.24e-12 4. pH = 1.37 pOH = 12.63 [H+] = 4.27e-2 [OH-] = 2.34e-13 5. pH = 9.1 pOH = 4.9 [H+] = 7.76e-10 [OH-] = 1.26e-5 |
6.
pH = 4 pOH = 10 [H+] = 1.0e-4 [OH-] = 1.0e-10 7. pH = 3.4 pOH = 10.6 [H+] = 3.98e-4 [OH-] = 2.51e-11 8. pH = 10.4 pOH = 3.6 [H+] = 3.98e-11 [OH-] = 2.51e-4 9. pH = 6.79 pOH = 7.21 [H+] = 1.62e-7 [OH-] = 6.2e-8 10. pH = 4.26 pOH = 9.74 [H+] = 5.49e-5 [OH-] = 1.82e-10 |